A nucleus _Z{X^A} emits an alpha-particle wit | vedclass

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(B) Initially,the nucleus is at rest,so the total initial momentum is $0$.By the law of conservation of linear momentum,the final momentum must also b

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$\frac{4v}{A - 4}$

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(B) Initially,the nucleus is at rest,so the total initial momentum is $0$.By the law of conservation of linear momentum,the final momentum must also be $0$.Let $M_d$ be the mass of the daughter nucleus and $M_{\alpha}$ be the mass of the $\alpha$-particle.The mass of the $\alpha$-particle is approximately $4$ units,and the mass of the daughter nucleus is $(A - 4)$ units.Let $v_1$ be the recoil velocity of the daughter nucleus.According to the conservation of momentum:$M_d v_1 = M_{\alpha} v$$(A - 4) v_1 = 4v$$v_1 = \frac{4v}{A - 4}$

$A$ nucleus $_Z{X^A}$ emits an $\alpha$-particle with velocity $v$. The recoil speed of the daughter nucleus is

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